Physics Review Question

Unit: Electricity and magnetism
Year: 1989 Question#: 20
Question: The potential difference between a pair of charged parallel plates 0.050 meters apart is 50 volts. What is the electric field intensity between the two plates?

(1 ) 1.0 x 102 N/C
(2 ) 2.5 x 102 N/C
(3 ) 5.0 x 102 N/C
(4 ) 1.0 x 10 3 N/C

What is this question really asking?




Explanation by: Cory V

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Answer 1
1.0 x 10 2 N/C

INCORRECT

Use formula E=V/d return to top























Answer 2
2.5 x 102 N/C

INCORRECT

Use E=V/d return to top



























Answer 3
5.0 x 102 N/C
INCORRECT

This answer is only half of the field intensity produced. Make sure to use E=V/d correctly. return to top


























Answer 4

1.0 x 103 N/C
CORRECT

1.0 x 10 3 N/C = 1,000 N/C wich is the volts divided by the given distance using formula E=V/d. return to top


























What's this question really asking?

What is the electric field intensity between a pair of parellel plates 0.050 meters apart that have a charge of 50 volts? return to top

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