Physics Review Question Unit: Electricity and magnetism Year: 1989 Question#: 20 Question: The potential difference between a pair of charged parallel plates 0.050 meters apart is 50 volts. What is the electric field intensity between the two plates? (1 ) 1.0 x 102 N/C (2 ) 2.5 x 102 N/C (3 ) 5.0 x 102 N/C (4 ) 1.0 x 10 3 N/C What is this question really asking? Explanation by: Cory V [ Return to question menu ] Answer 1 1.0 x 10 2 N/C INCORRECT Use formula E=V/d return to top Answer 2 2.5 x 102 N/C INCORRECT Use E=V/d return to top Answer 3 5.0 x 102 N/C INCORRECT This answer is only half of the field intensity produced. Make sure to use E=V/d correctly. return to top Answer 4 1.0 x 103 N/C CORRECT 1.0 x 10 3 N/C = 1,000 N/C wich is the volts divided by the given distance using formula E=V/d. return to top What's this question really asking? What is the electric field intensity between a pair of parellel plates 0.050 meters apart that have a charge of 50 volts? return to top |
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