Physics Review QuestionUnit:
MechanicsYear:
1989 Question#: 14
Question:
Gravitational force of attraction F
exists between two masses A and B when they are separated by a fixed distance. After
mass A is tripled and mass B is halved, the gravitational attraction between the
two masses is:(1
) 1/6 F(2
) 2/3 F(3
) 3/2 F(4
) 6 FWhat is this question really asking?
Explanation by: JD W. [ Return to question menu
]Answer 1
1/6 F INCORRECT Mass A has been tripled. So the force from A to B is increased 3 times. Mass B has been decreased by a half, so that increases the force between mass A and B by 1/2 so the force would not be1/6 F return to top
Answer 2
2/3 F INCORRECT Mass A has been tripled. So the force from A to B is increased 3 times. Mass B has been decreased by a half, so that increases the force between mass A and B by 1/2 so therefore the answer is not 2/3 F. return to top
Answer 3
3/2 F CORRECT Nice use of the formula . Mass A has been tripled. So the force from A to B is increased 3 times. Mass B has been decreased by a half, so that increases the force between mass A and B by 1/2 Combining the tripling and the halving you would get half of 3 which would look like (3/2) F return to top
Answer 4
6 F INCORRECT Mass A has been tripled. So the force from A to B is increased 3 times. Mass B has been decreased by a half, so that increases the force between mass A and B by 1/2 so the answer could not be 6 F. return to top
What's this question really asking?
This question is basically asking about gravitational force. If the initial force was equal, then mass A was tripled and mass B was decreased by half, what's the force of attraction now? return to top |

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